L3 · Theoretical probability: tree diagrams and tables
“I can find the theoretical probability of an event involving two independent events by building a tree diagram or a table, counting the favourable combined outcomes, and dividing by the size of the whole sample space.”
Flip two coins. What is P(both heads)? Step 1: Build the tree. First coin branches: H, T. Off EACH branch, the second coin branches again: H, T. Step 2: The tree has 4 ends - the sample space: HH, HT, TH, TT. All 4 are equally likely. Step 3: Favourable ends for "both heads": only HH - 1 end. Step 4: P(both heads) = 1/4 = 25%. Model both ways: the tree diagram drawn out in words (H -> H, H -> T, T -> H, T -> T), AND the same 4 outcomes as a 2 x 2 table - the tree and the table always agree. Say it plainly: the organizer does the counting honestly. Probability = favourable ends (or cells) / total ends (or cells).
In the two-coin tree, why are there 4 ends and not 2?
Using the same two-coin tree, find P(exactly one head). -> Favourable ends: HT and TH - 2 ends. P = 2/4 = 1/2 = 50%
"Two coins again: P(two tails) = favourable ends / total ends = 1 / ___ = ___." -> 1 / 4 = 1/4
10 scored questions with a 3-rung hint ladder. Mastery needs 8/10 plus both gate questions.